An ionized hydrogen atom $($net charge $=+e,$ where $e$ is the charge of the proton$)$ is accelerated through a potential difference of $6\mathrm{.}0$ V $.$ What is the increase in kinetic energy of the atom? $($Note: an electron$-$Volt, abbreviated eV$,$ is a unit of energy equal to the charge $+e$ of a proton times $1$ Volt$).$

$4$ eV

$0\mathrm{.}67$ eV

$6$ eV

$0$ eV

$24$ eV