Question: An object has a velocity 70 = 5.00 m/s + 2.00 m/s jat time t=0.00 s. The acceleration of the object is a(t) =



An object has a velocity 70 = 5.00 m/s + 2.00 m/s jat time t=0.00 s. The acceleration of the object is a(t) = (2.00 m/s) + (1.00 m/s) t). ift object is located at 10 = 1.00 m i - J. If the 1.00 m jat t=0.00 s. How far (in m) is the object from the origin at time t = 1.00 s? An object has a velocity V0 = 4.00 m/s + 4.00 m/s jat time t=0.00 s. The acceleration of the object is a(t) = (2.00 m/s) + (1.00 m/s) 2. the If object is located at 70 = 2.00 mi 4.00 m jat t=0.00 s. - How far (in m) is the object from the origin at time t = 1.00 s? A particle starts from the origin at t=0 with a velocity of 7.8 i m/s and moves in the xy plane with a constant acceleration of (-3.3 i + 4.8 j) m/s. At the instant the particle achieves its maximum positive x coordinate, how far (in m) is it from the origin?
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