Question: An object is launched straight upward from a platform.Its height above ground is h(t) = 12+v0t-4.9t^2 where h is in meters and t is in

An object is launched straight upward from a platform.Its height above ground is

h(t) = 12+v0t-4.9t^2

wherehis in meters andtis in seconds.Use the fact thath'(3)=0 to determine when the object hits the ground.

Be accurate to 2decimal places.Enter numerical answer only.No units.

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