Please answer 1-6 and show work the steps are shown for 1-4

1 In the projectile equation, h(t) = -16t2 + 12.3t + 4.9, what number indicates gravity in feet/sec?? Explain. 2 In the projectile equation in #1 above, what number indicates the height of the object above ground level when launched? Explain. 3. In Ex. 2 above, when does the object hit the ground? Show your work. See Ex. 1, B How long before the object hits the ground after launch? 4. In Ex. 3 above, when does the object hit the ground? Show your work. See Ex. 1, B How long before the object hits the ground after launch? Ex. 2 An object is launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. What will be the object's maximum height? When will it attain this height? Solution: Step 1 Set up the equation based on the information in the problem. h =-1612 + 64t + 80 Step 2 Find the vertex (time, height) = (t, h). 1-coordinate: 1= -b/(2a) = -64/(2*-16) = 2 h-coordinate: h= -16(2)2 + 64(2) + 80 = 144 Answer: It takes 2 sec for the object to reach the maximum height of 144 ft. Ex. 3 An object is launched from ground level directly upward at 39.2 m/s. For how long is the object at or above 34.3 meters? Solution: Step 1 Set up the equation based on the information in the problem. h =-4.912 + 39.21+ 0 Step 2 Since the height indicated as "at or above 34.3", seth = 34.3. 34.3 = -4.912+ 39.21 Step 3 Solve the equation for t. 4.912 - 39.21 + 34.3 = 0 4.9(12 - 81+ 7) = 0 4.9(t - 7)(t - 1) = 0 1- 7=0 t-1=0 t= 7. 1 Answer: The object is at or above 34.3 meters onds or for 6 seconds. 5. Find the zeros that would be marked on the number line for this inequality: x2 - 9