Question: Analyze the following code. int x = 0; if (x > 0); { cout < < x; } select correct awnser A.Nothing is printed because
Analyze the following code. int x = 0; if (x > 0); { cout << "x"; }
| select correct awnser A.Nothing is printed because x > 0 is false. | ||
| B.The symbol x is always printed. | ||
| C.The value of variable x is always printed. | ||
| D.The symbol x is always printed twice. |
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