Question: Analyze the following code. int x = 0; if (x > 0); { cout < < x; } Nothing is printed because x > 0

Analyze the following code. int x = 0; if (x > 0); { cout << "x"; } Nothing is printed because x > 0 is false. The symbol x is always printed. The value of variable x is always printed. The symbol x is always printed twice.

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