and $C{H}_4($Equation $(2)).$ Hydrogen yield $({}_{H2})$ is defined in

Equation $(3)$ where $R$ is the $\frac{H_2}{C}{O}_2$ reforming ratio of $\frac{7}{3}$ for

glycerol. This ${}_{H2}$ definition takes into account that $4H_2$

molecules come from one molecule of glycerol whereas $3$

molecules of $H_2$ proceed from water.

$x_G^t=\frac{F_G^{\text{I}}-F_G}{F_G^{\text{I}}}100$

$x_G^g=\frac{{\displaystyle \underset{?}{\overset{?}{}}}{}_i*F_i}{{}_G*F_G^{\text{I}}}100$

${}_{H2}=\frac{F_{H2}}{F_G^{\text{I}}}\frac{1}{R}100$

This should've been a follow up question, but chegg doesn't allow replies so I'll make another one. Assuming a $100$kg$/$hr $1$ hr basis of $10$ wt$\%$ glycerol $90\%$ water, $100\%$ glycerol conversion and $100\%$ hydrogen yield, and exit gas stream composition of $70\%$ H$230\%$ CO$2($according to the study I$\text{'}$m basing on$),$ how would the material balance equation look like? The answer I got was $253\mathrm{.}36$ mol H$2$ per $100$kg feed, as well as $108\mathrm{.}58$ mol CO$2,$ but I feel like the wording of the formulas confused me$.$