Question: Anova Two-Factor With Replication SUMMARY 3MM. 4MM. TOTAL 145 ___________________________________________________________ COUNT 6 6 12 SUM 57.89 56.66 114.55 AVERAGE 9.6483 9.4433 9.5458 VARIANCE 0.6445 1.8431

Anova Two-Factor With Replication

SUMMARY 3MM. 4MM. TOTAL

145

___________________________________________________________

COUNT 6 6 12

SUM 57.89 56.66 114.55

AVERAGE 9.6483 9.4433 9.5458

VARIANCE 0.6445 1.8431 1.1422

155

__________________________________________________________

COUNT 6 6 12

SUM 64.1 58.62 122.72

AVERAGE 10.6833 9.7700 10.2267

VARIANCE 3.3687 2.7493 3.00084

TOTAL

__________________________________________________________

COUNT 12 12

SUM 121.99 115.28

AVERAGE 10.1658 9.6067

VARIANCE 2.1163 2.1166

SOURCE OF VARIATION SS df MS F P- VALUE F CRIT

___________________________________________________________________________________________________

SAMPLE 2.7812 1 2.7812 1.2927 0.2690 4.3512

COLUMNS 1.8760 1 1.8760 0.8720 0.3615 4.3512

INTERACTION 0.7526 1 0.7526 0.3498 0.5608 4.3512

WITHIN 43.0284 20 2.1514

TOTAL 48.4382 23

At the 0.05 level of significance,

a.Is there aninteractionbetween the temperature and die diameter?

Null hypothesis

Alternative hypothesis

Decision

Conclusion

b. Is there an effect due todie temperature?

Null hypothesis

Alternative hypothesis

Decision

Conclusion

c. Is there an effect due todie diameter?

Null hypothesis

Alternative hypothesis

Decision

Conclusion

e. What conclusion can you draw from your analysis (overall conclusion)?

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