Question: answer please!!! At 1,600K, the equilibrium constant for the reaction below is Kc=0.215. Br2(g)2Br(g) What is the percent dissociation of Br2 at 1,600K, if the

answer please!!!

At 1,600K, the equilibrium constant for the reaction below is Kc=0.215. Br2(g)2Br(g) What is the percent dissociation of Br2 at 1,600K, if the initial concentration of Br2 is 0.750molL1 ? Give your answer accurate to two significant figures. Do not include the % sign as part of your answer. The percent dissocation of Br2 is %. Hints: 1. If the initial concentration of Br2 is C0 and the concentration of Br2 decreases by x (because of dissociation), then the percent dissociation of Br2 is equal to 100(x/C0). 2. You may have to use the quadratic formula to solve this problem. The quadratic formula, given below, can be used to find the solutions to the equation ax2+bx+c=0. x=2abb24ac

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