Answer the following question using Bayes' rule: p(A|B) = p(B|A)p(A) / p(B|A)p(A)+p(B|A)p(A)

You are presented with three coins. You are told that two of them are fair, meaning that if flipped, they will return heads or tails with a 0.5 probability. You are also told that one is weighted, and will return heads 0.75 of the time and tails 0.25. You pick one coin arbitrarily and flip it; it returns heads. Calculate the probability that the coin you are holding is the weighted one, given that it returned heads on one flip.