Question: Answer the following two questions based on the transshipment network given below. Observe that nodes 1, 2, and 3 are supply nodes, 4 and 5

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Answer the following two questions based on the transshipment network given below. Observe that nodes 1, 2, and 3 are supply nodes, 4 and 5 are transshipment nodes and finally, 6 and 7 are demand nodes. Numbers on the arcs represent the cost of shipping one unit along the arc. Decision variables are defined as follows: Xij = the amount shipped from node i to nodej. 3 500 6 -600 5 9 400 2 6 12 5 2 15 8 7 -600 300 3 10 Assume that you formulate this transshipment problem as an LP. What is the objective function? O A. Min 3x16+ 2x14 + 3x15 + 5x24 + 6x25 + 2x32 + 8x 34 + 10x35 + 5x46+9x47 + 12x56 + 15x57 B. Max X16+X14 +X15+X24 + X25+ x32 + x 34 +X35 +246 +47 +856 +X57 O C. Max 3x16+ 2x14 + 3x15 + 5x24 + 6X25 + 2x32 + 8x 34 + 10x35 + 5x46 +9x47 + 12x56 + 15x57 O D. Min 3x61 + 2x41 + 3x51 + 5x42 + 6x52 + 2x23 + 8x 43 + 10x53+ 5x64 + 9x74 + 12x65 + 15x75 O E. Min X16+ X14 +X15+ X24+x25 + x32 + x 34 +X35+X46 +x47 +856 +857 Formulate the conservation of flow constraint for node 3. A. 2x32 +8X34 + 10x35 = 300 X3252 OB. X34 58 X35 5 10 C. -X32 - X34 - X35 = 300 D.X32 + x34 +X35 = 300 E. X32 - X34 - X35 = 300 Formulate the conservation of flow constraint for node 4. A. X46 + x47- (X14 + x24 + x34) = 0 OB. X46 + X47 +X14+x24 + x34 = 0 OC. X46+X47 - (X14 + x24 + x34) = 5+9-2-5-6 OD. X46 + X47 + X14 +X24 + x34 = 1200 O E. 5x46+9x47 - (2x14 + 5x24 + 6x34) = 0 QUESTION 42 Formulate the conservation of flow constraint for node 6. A. -X16 - X46 +X56 = 600 OB. -X16 - X46 - X56 = -600 X16 = 3 OC. X46 55 X56 59 D. -X16 - X46 - X56 = 600

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