QUESTION 31 Answer the following two questions based on the transshipment network given below. Observe that nodes 1, 2, and 3 are supply nodes, 4 and 5 are transshipment nodes and finally, 6 and 7 are demand nodes. Numbers on the arcs represent the cost of shipping one unit along the arc. Decision variables are defined as follows: Xiyathe amount shipped from node i to nodej. 3 500 -600 3 9 400 0 12 2 15 8 -600 3001 3 10 Assume that you formulate this transshipment problem as an LP. Answer Questions 31-34 based on this information What is the objective function? Answer Questions 31-34 based on this information, What is the objective function? O A. Min 3x16+2x14+ 3x15 +5x24 + 6x25+2x32 + 8x 34+ 10x355x469x47-12x56+15x57 O B. Max X16+x141x15+X24 + x2 + x32+ x 34+x35+X46 - 47+x56x57 OC. Min X16+X14+x15 +*24 + x2 + x32+x 34+ x3 + x46 +47 +X56X57 OD. Max 3x16+ 2x14 + 3x15 75x24 +6X25+2x32 + 8x 34 + 10x35 +5x46 + 9x47 + 12x56 + 15x57 O E. Min 3x61 +2X41+ 3x51+5x42 + 6x52+2x23 + 8x 43 + 10x53 5x649x74 + 12x65 +15x75 QUESTION 32 Formulate the conservation of flow constraint for node 2 O A. - 24 - 25 + x32 = 400 OB.X24+x2532 - 400 O C.x24 5 X25 s6 X322 O D.5x24 + 6x25 - 2x32 - 400 O E. X24+x25 - 32 - 400 QUESTION 33 Formulate the conservation of flow constraint for node 4. O A. x46+ x47 - (x14 + x24 + x34) = 54-9-2-5-6 OB.X46+ x47+x14+x24 + x34 = 1200 O C.5x46+9x47 - (2x14 + 5x24 + 6x34) = 0 O D.x46+x47-(x14 + x24 + x34) = 0 O E. x46+ x47+ x14+x24 + x34 = 0 QUESTION 34 Formulate the conservation of flow constraint for node 7. O A.x56 - #57 - 600 O B.X56 S 9 X57 s 15 O C. 12x56 + 15x57 600 OD.-X47 - X57 = - 600 O E. 9x56 + 15x57-600