Answer the question using the formulas provided

Em = Eg + Ek EQ =RX 2 Fe = kx mik , + movie = myvi , + myviz p = mv Ft = Ap 2m2 K. = my + my K = my 2m my + 12 V. = my + m2 Fa =- Gm, m2 FF = kq192 7-2 G = 6.67 x 10-11 Nm2/kg2 k = 8.99 x 109 GMplanet g =- FE = qE Gm kqz 8 = - 7-2 AE = -qEAd kq192 EF = - r EE V = AE = kq192 ( 7 - -) AEE AV= FM = quB sin e AV Fon wire = ILB sin e E Ad my r=- kq aB V Z n =- d sin 8 = ma c = 3.00 x 10# m/s d sin e = (n -7) a n, sin 01 = n2 sin 02 Ax = LA n2 sin ec 712 2t N =- Asn = [PS1 - PnS2l = (n -=)a 2t = - nfilm sin On = (n - 2) (m + = )a 2t = nfilm Xn sin On = L sin 0 = na T = -4)4 (m + z) 1 sin em W d sin 0 = ml Ay = AL 24y = =h d sine = (n - 7)a v = Af W = ml = w sin em1. A 23kg block slides 18 m on level ground before coming to rest. If 430J of work are done by friction, calculate the coefficient of friction between the block and the ground. (8)