Question: Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,100 pounds and
Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,100
pounds and standard deviation 90
pounds.
a. What is the probability that demand will exceed 900
pounds?
b. What is the probability that demand will be between 1,000
and 1,200
pounds?
c. The probability is 0.15
that demand will be more than how many pounds?
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Click the icon to view the standard normal table of the cumulative distribution function.
a. The probability that demand will exceed 900
pounds is ______ .
(Round to four decimal places as needed.)
b. The probability that demand will be between 1,000
and 1,200
pounds is _____.
(Round to four decimal places as needed.)
c. The probability is 0.15
that demand will be more than ____ pounds.
(Round to one decimal place as needed.)
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