Question: Ap stat A *No explanation needed 1) Jack is the head groundskeeper of a golf club that has several different courses. One day he is
Ap stat A
*No explanation needed
1)












Jack is the head groundskeeper of a golf club that has several different courses. One day he is instructed by the owner to cut 10 greens and that he should spend only one hour on each green. For a par 3 green there is a 0.80 probability that he will have it cut in one hour. For a par 5 green there is a 0.60 probability that he will have it cut in one hour. If Jack's job consists of preparing six par 3 greens and four par 5 greens, what is the probability that he will have at least 9 of them cut in the allotted time? O 0.0311 0.0396 0.0651 O 0.0991 0.1331Suppose that a test for Hepatitis C is 98% accurate in that if a person has Hepatitis C, the test will indicate "positive" with 0.98 probability, and if a person does not have Hepatitis C, the test will indicate "negative" with 0.98 probability. The percentage of the population that has Hepatitis C is 0.007. Based on these probabilities, if a person tests positive for Hepatitis C, what is the probability that the person actually has Hepatitis C? O 0.0069 0.2567 0.3454 0.9604 0.9800A Los Vegas slot machine requires 25 cents to play. It gives payouts, per play, based on the following probabilities: Pay out in $ 0.00 0.25 1.00 10.00 Probability 0.88 0.08 0.03 0.01 What is the expected amount of money gained per play from this slot machine? O- 0.10 O - 0.01 0.04 0.15A coin is weighted so that the probability of heads is 0.60 and the probability of tails is 0.40. The coin is tossed six times and the number of heads out of six is recorded. This process is repeated 200 times. Which of the following tables is the most likely distribution of the results? Heads O 1 2 3 4 5 6 Number 28 28 29 29 29 29 28 Heads O 1 2 3 4 5 6 Number 40 28 12 11 13 35 61 Heads 0 1 2 3 4 5 16 Number 10 18 22 28 30 44 48 Heads 1 2 3 5 6 Number 1 6 27 57 65 33 9 Heads O 1 2 3 5 6 Number 0 0 5 78 84 31Scores on two exams are approximately normally distributed. Two hundred forty students took the Chemistry exam which had a mean of 76 and a standard deviation 14. Two hundred ten students took the Physics exam which had a mean of 72 and a standard deviation of 16. Approximately how many students, total, had scores of 89 or above? 65 72 0 77 84 O 91The voltages for a population of a type of battery follows a normal distribution. It is determined that 10% of the voltages exceed 12.513 volts, and 1% of the voltages exceed 12.930. What are the mean and standard deviation of this population of battery voltages? Ou = 12.0, 0 = 0.2 Ou = 12.0, 0 = 0.4 Ou = 12.2, 0 = 0.1 Ou = 12.2, 0 = 0.2 u - 12.2, 0 = 0.4Moren's Department Store has a special sale whereby each customer, upon checkout, chooses a random ticket that is labeled 5%, 15%, or 25%. The customer is then allowed to take a discount of that amount from the total sale. ten percent of th tickets are labeled 25%, 20% are labeled 15%, and the remaining are labeled 5%. Excluding sales tax, what is the expected actual sale for a customer wishing to purchase $200 worth of merchandise? $134 $154 O $170 $182 $190Michael's teacher informed him that his score of 98 on the last Algebra test corresponded to a z-score of -2.12. Which of the following is the best interpretation of Michael's result? Michael did very well on this test in relation to the class. Michael did very poorly on this test in relation to the class. Michael scored somewhat above average in relation to the class. Michael scored a little below average in relation to the class. )Michael's score was very close to the class average.Suppose the events A, B, and C are all mutually exclusive events. What would be the probability of P(A and B, or C)? Oo P(C) O P(A)P(B) + P(C) P(A) + P(B) - P(C) P(C) + 1 -(P(A) - P(B)It has been determined that there is a strong linear relationship between the weight of a certain breed of monkey and its height. From a random sample of monkeys, a least squares regression line was computed, relating the monkey's weight, y, in pounds, with its height, x, in inches. The regression line was: Weight = -16.88 + 2.13 Height 20
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