Application of Newton's Laws including friction F 40 FN weight 40 F It is extremely helpful...

    

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Application of Newton's Laws including friction F 40 FN weight 40 F It is extremely helpful to make a table like this, fill in each item (use "space holders" for unknown quantities) F = F, = Nx fx = W = EF, F+F+S,+W, EF, Newton's EF = ma_ 2nd law f = W F, + F + S +W EF, =ma, Previously you solved the problem "Pull a suitcase - NO Friction". Now you learn how to take into account friction. A suitcase is initially at rest on a ROUGH horizontal floor. A force F is exerted on the suitcase trying to make it move. The coefficient of static friction between the suitcase and the wood floor iss=0.57. The coefficient of kinetic friction is 0.47. The suitcase' mass is m = 24.2 kg, The magnitude of the gravitational acceleration is 9.80 m/s. The magnitude of Fis F = 70.0 N. What is the magnitude of the ACTUAL Static frictional force? Note: the formula fs,max = FN is ONLY valid when the object is on the VERGE of moving, which is NOT the case here. Common mistakes are usually made here. Keep 2 digits after the decimal point. Unit is Newtons. ACTUAL static friction fs N To make it easier for the suitcase to move, some lubricant is spead on the bottom side of the suitcase to reduce the coeffcient of friction. The NEW coefficient of static friction between the suitcase and the wood floor is fsnew = 0.26. The new coefficient of kinetic friction is knew = 0.19. Under the same magnitude of the pulling force F = 70.0 N, the suitcase moves on the floor. Part I - New situation: Look at what you did in Part E. Does the magnitude of the Normal force change? Enter its value. Keep 2 digits after the decimal point. Unit is Newtons. FN = Submit VE Request Answer Keep 2 digits after the decimal point. Unit is Newtons. Submit Part J - New situation: What is the magnitude of the Kinetic frictional force? New situation fknew 17 ? Request Answer N ? N Application of Newton's Laws including friction F 40 FN weight 40 F It is extremely helpful to make a table like this, fill in each item (use "space holders" for unknown quantities) F = F, = Nx fx = W = EF, F+F+S,+W, EF, Newton's EF = ma_ 2nd law f = W F, + F + S +W EF, =ma, Previously you solved the problem "Pull a suitcase - NO Friction". Now you learn how to take into account friction. A suitcase is initially at rest on a ROUGH horizontal floor. A force F is exerted on the suitcase trying to make it move. The coefficient of static friction between the suitcase and the wood floor iss=0.57. The coefficient of kinetic friction is 0.47. The suitcase' mass is m = 24.2 kg, The magnitude of the gravitational acceleration is 9.80 m/s. The magnitude of Fis F = 70.0 N. What is the magnitude of the ACTUAL Static frictional force? Note: the formula fs,max = FN is ONLY valid when the object is on the VERGE of moving, which is NOT the case here. Common mistakes are usually made here. Keep 2 digits after the decimal point. Unit is Newtons. ACTUAL static friction fs N To make it easier for the suitcase to move, some lubricant is spead on the bottom side of the suitcase to reduce the coeffcient of friction. The NEW coefficient of static friction between the suitcase and the wood floor is fsnew = 0.26. The new coefficient of kinetic friction is knew = 0.19. Under the same magnitude of the pulling force F = 70.0 N, the suitcase moves on the floor. Part I - New situation: Look at what you did in Part E. Does the magnitude of the Normal force change? Enter its value. Keep 2 digits after the decimal point. Unit is Newtons. FN = Submit VE Request Answer Keep 2 digits after the decimal point. Unit is Newtons. Submit Part J - New situation: What is the magnitude of the Kinetic frictional force? New situation fknew 17 ? Request Answer N ? N