Question: AR 1 8 1 3 . 8 Streptococcus lactis 5 L 5 g / L 0 . 1 g / L m = 0

AR18
"13.8 Streptococcus lactis 5 L 5 g/L 0.1 g/L
m =0.2 h-1 KS =200 mg/L kd =0.002 h-1 YFX/S =0.4 g-X/g-Sp =0.1g
a S X P
g/(day-L)3.5"

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