Assigning a value of 20 to the objective function, 10, making 4X1+20X2=20 the fine for the objective function goes through the following two pointe (1,0) and (5,0) (0,1) and (0,5) (1,0) and (0,5) (5,0) and (0,1) none of the above QUESTION 13 The feabible regan of tis problem is unbounded. it a straight ine segmont. containe the origin. all of the above none of the above. This problem does not have a feasible solution. has altemative optimal solutions. has an unbounded objective function. has a unique, ie., a single, optimal solution. none of the above. QUESTION 15 The point (90/19,20/19) is feasible but not optimal. infeasible. optimal. not an intercept point. none of the above. The point (6,3) is feasible. not on the boundary of the feasible region. not optimal. all of the above. none of the above. QUESTION 17 The point (3,1) satisfies the first constraint but not the other two. the second constraint but not the other two. the third constraint but not the other two. all three constraints. none of the above. The point (10,0) is feasible but not optimal. an optimal solution. infeasible. not on the boundary of the feasible region. none of the above. QUESTION 19 The value of the objective function asthe point (90/19,20/19) is 40 360/19 400/19 not determined none of the above The optimal objective function value is 4 20 40 80 cannot be determined