ASSIGNMENT 2 PART 1 PA Isothermal process PB B -V (liters) VA VB A 1.00-mol sample of an ideal monatomic gas is taken through the three -stage cycle as shown The process A to B is a isothermal expansion. PA = 53/10, PB = 11/10, VA = 11, VB = 53. Calculate net work done by the engine in a whole cycle in kJ. Round your answer to the nearest hundredth (i.e. if your answer is 1.875, round it to 1.88). Take 1 atm = 101300 Pa. Note: Remember about the accepted sign convention (if the energy flow in the form of work leaves the system --> W0).P(aton ) Gruen that, P A PA = 32 atm = 5.3 atm Isothermal process PB = 11 atu = 101 atm PB B VA 2 11 * 10 3 in3 V (liters ) VA VB VB = 53 x 10 3 m3 I NM = 101300 PA , IL 2 1X105 m3 . The work done on process A- B which is roothermal. WAB = - PAVA In (VB ) = - 5.3 * 101300 x 11 x 10 : In ( 53 2 - 9. 29 x 103 J The work done on process 13-C is reobank . wise = - PB . ('VA - VB ) = - 1.1 x 10 1300 x ( 11- 53 ) x10" = 4. 68 x 10 J an process c-A is isochoare, so there is no work done. INCA 2 0 : Net work done is If because of decreasing of volume ). Wine- 2 - WAB - WBC = ( 9. 29 - 4. 68 ) KJ 2 4. 61 KJ .: So, the net work done by the engine in a whole Cycle is 1 4 . 61 KJ