Assignment 3 Alternative Model Summary In this assignment you are provided information on an experiment and you are re- 5 R-sq R-sq[adj) R-sq[pred) 4.71669 91.99% 84.79%% 75.66% quired to investigate and interpret the output which is provided below. Problem: Consider the three-variable central composite design shown in the table. Run Time (min) Temperature [*c) Catalyst (9%) Conversion (96) y1 Activity y2 1 -1.000 -1.000 -1.000 74 53.2 Fits and Diagnostics for Unusual Observations 1.000 -1.000 -1.000 51 62.9 Conversion Std -1.000 1.000 -1.000 53.4 Obs % (y1) Fit Resid Resid 1.000 1,000 -1.000 70 62.6 20 91 00 81.09 9.91 230 R -1.000 -1.000 1,000 71 57.3 1.000 -1.000 1.000 90 67.9 R Large residual -1.000 1.000 1.000 66 59.8 1.D00 1,000 1.000 97 67_B 0.000 0.000 0.000 81 59.2 Analysis of Variance D.ODO 0.000 0.000 75 60.4 Source DF Adj 55 Adj MS F-Value P-Value 11 0.000 0,000 0.000 76 59.1 Model 9 2555.73 283.97 12.76 12 0.0DO 0.000 0.000 83 60.6 Linear 3 763.05 254.35 11.43 0.001 13 -1.682 0.000 0.000 76 59.1 A 14.44 14.44 0.65 0.439 14 1.682 D.000 0.000 79 65.9 222.96 222.96 10 02 0.010 15 D.0DO -1 682 0.000 85 525.64 525.64 23.63 0.007 60 16 D.DDO 1.682 0.000 97 60.7 Square 3 601.30 200.43 48.47 40.47 0.17 17 0.000 D.000 -1.682 55 57.4 124.48 124.48 5.60 3040 18 0.000 0.000 1.682 81 63.2 CC 380.59 384 59 17.47 0.002 19 0.000 0.000 0.000 60.B 2-Way Interaction 3 1191.37 397.12 17.85 0.000 20 0.000 0.000 91 58.9 36.12 36.12 .62 D.231 AC 1035.12 1035.12 0.000 B*C 120.13 120.13 5.40 0.043 Design and Analysis of Experiments (9th Edition) [Texidium version]. (2017). Re- Error 10 22247 22.25 trieved from http://texidium.com Lack-of-Fit 5 56.47 11.29 034 0.869 Pure Error 5 165.00 33.20 Total 19 2778.20 Part 1- Conversion percent A partial Minitab output for the full model is shown below