Assume a specific gas constant of 2077Jkg -1 K -1 a mass of 1kg and C v
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Assume a specific gas constant of 2077Jkg-1K-1 a mass of 1kg and Cv=717Jkg-1K-1
Date for closed thermodynamic systems (sterling engine)
Temperature volume(m3)
Learner 13=3 | Heat energy input (Qin)(j) | Cold(k) | Hot(k) | Maximum (Vmax) | Minimum (Vmin)(m3) |
3 | 4000 | 403 | 600 | 0.6 | 0.3 |
Date for heat exchanger temperature
Learner 13=3 | Heat energy input (Qin)(j) | Cold(k) | Hot(k) | Exchanger Volume(m3) | Heat coefficient (U) (Wm-2K-1) |
3 | 800 | 303 | 500 | 0.6 | 0.3 |
Calculate work done.
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