Question: Assume k is one-to-one function... and k'(k^-1(c) = 0 for some real number c where k^-1 is the inverse function of k. Show k^-1 is

Assume k is one-to-one function... and k'(k^-1(c) = 0 for some real number c where k^-1 is the inverse function of k. Show k^-1 is not differentiable at c using a proof by contradiction.

Hints:

remember k(k^-1(x)) = x

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