Assume that OS uses 2 level paging with page size 10. Map given logical address to physical one using the outer page table and pysical memory content between address 100 and 320 given below.

Outer Page Table

10

19

Memory Content (to save space, it is shown in rectangular form, i.e. content of address 100 is 31, 101 is 21, 111 is 41, etc.)

Logical address 151 maps to ...... ????

ps: No explanation needed just answer

0 1 3 4 5 6 7 8 9 Address 100 31 21 2 26 23 25 39 28 33 15 30 11 45 41 20 16 31 110 120 130 18 39 46 32 41 21 29 19 28 24 46 20 21 15 39 12 11 19 5 2 | Q 12 10 44 19 32 48 45 29 36 31 47 22 29 35 33 46|| 33 25 13 38 19 49 39 37 4 40 36 50| 40 28 13 16 47 18 12 11 28 41 18 32 22 33 6 21 40 12 25 17 44 25 46 46 43 49 4 22 140 150 160 170 180 190 200 210 220 230 240 250 260 270 33 15 39 26 29 19 15 29 17 11 29 46 10 22 25 30 30 22 22 20 25 18 12 19 12 20 42 50 43 16 31 27 35 36 48 16 50 39 35 41 31| 12 48 13 15 13 38 38 35 49 20 26 50 48 16 19 35 14 26 44 15 13 43 23 20 47 15 45 46 49 40] 19 42 43 42 41 30| 47 29 16 16 15 46 37 24 37 25 50 43 280 35 24 44 41 33 42 290 31 45 40 | 33 21 32 6 33 27 33 34 24 34 41 26 14 10 20 46 15 19 25 27 26 22 3001 29 26 18 14 21 44 22 41 36 33 310 320 47 28 10 42 26 41