Assume the PC station is $12+25\mathrm{.}32ft.,$ the degree of curvature is $10$ degrees, and the length of curve is $638\mathrm{.}90$ ft $.$

What should the deflection angle from the PC to the PT be$?$

$($a$)10-00-00$

$($b$)31-56-42$

$($c$)63-53-24$

$($d$)80-60-60$

What should the sub chord from the PC to the PT be$?$

$($a$)606\mathrm{.}31$

$($b$)631\mathrm{.}31$

$($c$)638\mathrm{.}31$

$($d$)638\mathrm{.}90$

What should the deflection angle from the PC to the midpoint of the curve be$?$

$($a$)15-58-21$

$($b$)31-56-42$

$($c$)40-00-00$

$($d$)63-53-24$

What should the sub chord from the PC to the midpoint of the curve be$?$

$($a$)311\mathrm{.}13$

$($b$)315\mathrm{.}33$

$($c$)317\mathrm{.}40$

$($d$)319\mathrm{.}45$

What is the deflection angle from the PC to the first $50ft.$ station?

$($a$)0-37-01$

$($b$)1-14-63$

$($c$)1-51-04$

$($d$)2-30-00$

What is the sub chord from the PC to the first $50$ ft $.$ station?

$($a$)24\mathrm{.}61$

$($b$)24\mathrm{.}68$

$($c$)49\mathrm{.}91$

$($d$)50\mathrm{.}00$

You are occupying station $14+25\mathrm{.}32,$ backsighting the PC$,$ flopping your scope, zeroing the horizontal circle, and measuring clockwise

horizontal angle to station $16+25\mathrm{.}32.$ This deflection angle is

$($a$)10$ deg.

$($b$)20$ deg.

$($c$)30$ deg $.$

$($d$)40$ deg.