Assume you are using R and the arules apriori algorithm. Next, assume that you have thousands of transactions and six possible elements: "bread", "milk", "diapers", "coke", "quinoa", and "beer". Assume that you run the apriori algorithm with the following line of code:

MyRules $=$ arules::apriori$($MyTransactions$,$ parameter $=$ list$($support$=\mathrm{.}35,$

confidence$=\mathrm{.}5,$ minlen$=2))$

Which of the following is false?

Question $6$ options:

a$)$

If $\{$bread $\}->\{$diapers$,$ milk$\}$ is a rule that the apriori algorithm includes in MyRules, then $\{$bread$\}->\{$diapers$\}$ must also be a rule included in MyRules.

b$)$

$\{$bread$\}->\{$quinoa$\}$ is one of many possible rules that apriori will consider.

c$)$

If $\{$bread$\}->\{$quinoa$\}$ has a confidence of $\mathrm{.}3$ and a support of $\mathrm{.}25$ it will not be included in MyRules by the apriori algorithm.

d$)$

If $\{$bread$,$ beer$\}->\{$diapers$\}$ is a rule that the apriori algorithm includes in MyRules, then $\{$bread$,$ beer$\}->\{$diapers$,$ coke$\}$ must also be a rule included in MyRules.

e$)$

If $\{$bread$\}->\{$quinoa$\}$ is not a viable rule because the support is $\mathrm{.}25,$ then $\{$bread$,$ milk$\}->\{$quinoa$\}$ is also not viable per the apriori algorithm.