Assume you are using R and the arules apriori algorithm. Next, assume that you have thousands of transactions and six possible elements: "bread", "milk", "diapers", "coke", "quinoa", and "beer". Assume that you run the apriori algorithm with the following line of code:

MyRules $=$ arules::apriori$($MyTransactions$,$ parameter $=$ list$($support$=\mathrm{.}25,$

confidence$=\mathrm{.}35,$ minlen$=2))$

Which of the following is false?

Question $18$ options:

a$)$

If $\{$milk$\}->\{$diapers$\}$ is not a viable rule because the support is $\mathrm{.}15,$ then $\{$milk$\}->\{$diapers$,$ quinoa$\}$ is also not viable per the apriori algorithm.

b$)$

If $\{$bread$,$ milk$\}->\{$diapers$\}$ is a rule that the apriori algorithm includes in MyRules, then $\{$bread$,$ milk$\}->\{$diapers$,$ coke$\}$ must also be a rule included in MyRules.

c$)$

If $\{$beer$\}->\{$quinoa$\}$ has a confidence of $\mathrm{.}25$ and a support of $\mathrm{.}2$ it will not be included in MyRules by the apriori algorithm.

d$)$

If $\{$bread$\}->\{$diapers$,$ beer$\}$ is a rule that the apriori algorithm includes in MyRules, then $\{$bread$\}->\{$diapers$\}$ must also be a rule included in MyRules.

e$)$

$\{$milk$\}->\{$coke$\}$ is one of many possible rules that apriori will consider.