At $25$ degree C temperature, $0\mathrm{.}6$ mole N$2$O$4$ is produced in the reaction of N$2$O$4($g$)=2$NO$2($g$)$ at equilibrium in $6$L pot. What will be the percentage of N$2$O$4$ in $8$L pot if temperature is kept constant? $\{$Pressure is inversely propoortional to volume of pot $\}$ ANSWER is $31\mathrm{.}11\%$