At $448C$ the equilibrium constant $K_c$ for the reaction is $50\mathrm{.}5.$

$H_2(g)+I_2(g)2HI(g)$

Predict in which direction the reaction will proceed to reach equilibrium at $448C$ if we start with $2\mathrm{.}0{10}^{-2}$mol of $HI,1\mathrm{.}0{10}^{-2}$ mol of $H_2,$ and $3\mathrm{.}0{10}^{-2}$mol of $I_2$ in a $2\mathrm{.}00-L$ container.