Question: At 73 o C the equilibrium constant for the reaction: 2 HI(g) H 2 (g) + I 2 (g) is K P = 6.31e-11. If

At 73 ^oC the equilibrium constant for the reaction: 2 HI(g) H₂(g) + I₂(g)

is K_P = 6.31e-11. If the initial pressure of HI is 0.00283 atm, what are the equilibrium partial pressures of HI, H₂, and I₂? p(HI) = p(H₂) = p(I₂) =

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