At a specific instance, a car is

travelling on a paved surface

at $V=140k\frac{m}{h}$ with $C_D=$

$0\mathrm{.}35,A_f=1\mathrm{.}90m^2,$

$W=6400N$ and $=1\mathrm{.}225$

$k\frac{g}{m^3}.$ Its engine is producing

$120$ hp of power and the

coefficient of losses between

the motor and the wheels is

$90\%.$ What will the car's

maximum acceleration rate be

under these conditions on a

level road? $($Use the

relationship $($F$\_$e$=($P$\backslash$times E$)/$V$)$

where $Fe$ is the force

generated by the engine in $N,P$

is the power in watts, V is the

vehicle speed in $\frac{m}{s}$ and $lon$ is

the coefficient of losses

between motor and wheels$).$

$(3$ decimal places$)$

The force to overcome

resistance $F_{\text{r}\text{e}\text{q}}=$

The effective force produced

by car engine $F_e=$

N

The maximum acceleration rate $a$

$=\frac{m}{s^2}$