Question: At a time oft = 2 . 2 5 s , a toy truck has a velocity vector of 4 . 1 7 m /

At a time oft =2.25 s, a toy truck has a velocity vector of 4.17 m/s in the direction 23.4 south of east. At a time oft =7.44 s, the truck has a velocity vector of 1.21 m/s in the direction 11.9 east of north. For the interval from t =2.25 s to t =7.44, calculate the average acceleration vector of the truck. Specify the magnitude of this average acceleration vector in units of meters/second?. Specify the direction of this average acceleration vector using the same kind of terminology as that underlined in the first two sentences of this problem.

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