At time t $=0,$ a $6\mathrm{.}14$ kg particle has position vector $=(4\mathrm{.}00$m$)-(4\mathrm{.}00$m$)$ relative to the origin. Its velocity is given by $=(-1\mathrm{.}322$m$/$s$)$ for t in seconds. About the origin with t $=19\mathrm{.}2$ s$,$ what are $($a$)$ the particle's angular momentum and $($b$)$ the torque acting on the particle, both in unit$-$vector notation?