Question: At time t = 0, a 1.26 kg particle has position vector 7= (5.00 m)-(3.00 m) relative to the origin. Its velocity is given by

At time t = 0, a 1.26 kg particle has position vector 7= (5.00 m)-(3.00 m) relative to the origin. Its velocity is given by = (-9.19t m/s ) i fort in seconds. About the origin with t = 14.9 s, what are (a) the particle's angular momentum and (b) the torque acting on the particle, both in unit-vector notation?

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