Question: At time t = 0 , an electron with kinetic energy 1 6 keV moves through x = O in the positive direction of an

At time t =0, an electron with kinetic energy 16 keV moves through x = O in the positive direction of an x axis that is parallel to the
horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 74.5 T.(a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance
from the x axis in centimeters when the electron reaches coordinate x =16 cm?

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