Question: At time t = 0 t = 0 t = 0 , an electron with kinetic energy 1 6 keV 1 6 ,

At time t=0t =0t=0, an electron with kinetic energy 16keV16\,\mathrm{keV}16keV moves through x=0x =0x=0 in the positive direction of an xxx-axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has a magnitude 46.2T46.2\,\mu \mathrm{T}46.2T.
(a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field?
(b) What is the electron's distance from the xxx-axis in centimeters when the electron reaches coordinate x=17cmx =17\,\mathrm{cm}x=17cm?

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