Question: atm abs H 2 S T K . . PG 1 2 1 0 0 / H 2 S y 2 = 0 . 2

atm abs H2S T K.. PG12100/ H2S y2=0.20.300/..: . P =1. T =293 K P =2 T-313 K 2: 95% HS.-1. T =293 K P-2-313

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