b. Evaluate the surface charge density numerically if Vo = 511 V and the sphere's diameter is 27 cm. 0= HC/m2 abc sin(x) Ox10 Submit Reset Reset All Note the specified units. c. Using the values from part b, at what distance / will the potential due to the sphere be 9.2 V? 5 r = m abc sin(x x10 Submit Reset Reset AllSet 7 Problem 4 Potential of a Charged Spherical Shell A hollow spherical conductor, carrying a net charge +@ = 49 pC, has inner radius 1 = 5.1 cm and outer radius r2 = 13 cm. At the center of the sphere is a point charge +Q/2. a. Find the potential at r = 18.0 cm. O. V = 3.225 V abc sin(x) Ox10 3.225 Submit Reset Reset All First, use Gauss' law to find the electric field in each region. Then, integrate to find the potential, using the fact that the electric potential is zero an infinite distance from the sphere. b. Find the potential at r = 10.0 cm. V = 5.09 V OK abc JX10' 5.09 V Submit Reset Reset All