Question: b x a(x + 1) + b a(x + 1) + x^2 (-a(x + 1)) - x a(x + 1) -x=0 has three roots x_1,

b x a(x + 1) + b a(x + 1) + x^2 (-a(x + 1)) - x a(x + 1) -x=0 has three roots x_1, x_2 and x_3. now since x_1*x_2*x_3=ab and we want solutions for ab>0 then either one root is >0 or all 3 >0

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