B1 = B1 (-i) where it is cut off on the right side second line

MY NOTE (3 Points] DETAILS A very, very long, straight wire carries a current I1, through the origin and along the z-axis. At the point (0, a, 0) on the positive y-axis (in the xy-plane), the magnetic field due to current I is in the negative-x direction and given by B, = Bj( 5.40 UT(-1) = 5.40 x 10-6 T(-1). (Hint: diagram this system by sketching the xy-plane in the plane of your paper, and z-axis perpendicular to that plane.) Constant Ho = 47 x 10- Tm/A. .) If a = 5.50 cm = 0.0550 m, what is the magnitude and direction of current I1? I1 A in the direction ) Next, a second very, very long, straight current-carrying wire, running parallel to current ], (that is, parallel to the z is), is added to the system so that the net magnetic field due to both currents is equal to zero at the point (0, a, 0) or positive y-axis. As before, a = 5.50 cm = 0.0550 m. second wire carries current 12 = 3.50 A in the negative-z direction through the point (0, y2) in the xy-plane (that is ough a point on the y-axis). What is the coordinate location of the second wire? Please enter your answer as the y- ordinate of the point (0, y2), in units of meters. I2 goes through the point yz = m, on the y-axis. DETAILS MY NOT