Balls on a line For this problem use G = 6.67 x 10-1l N m2 / kg2. Two balls are placed on the x-axis, as shown in the picture. The ball at x = -4a has a mass of 25m, while the ball at x = +2a has a mass of m. 25m m -4a -3a -2a -a O +a +2a +3a +4a (a) Homework . Unanswered . Due Dec 12th, 12:15 PM Use these numbers: m = 1.50 kg and a = 5.00 m. At what location on the x axis, a finite distance from the original two balls, could a third ball be placed and feel no net force because of the original two balls? X= m Type your numeric answer and submit x"Open in ReadingFor the next part you should work out the answer (a net force) in units of piconewtons (PN). 1 pN = 1x 10-12 N. The fact that we have to use piconewtons here really tells us how small gravitational forces are between everyday objects. Part (b) A Homework . Unanswered . Due Dec 12th, 12:15 PM Let's say a ball with a mass of 4m is placed at the location you found in part (a). With that third ball present in the system, what is the magnitude, in piconewtons, of the net force exerted on the 25m ball by the other two balls? PN Type your numeric answer and submit Unanswered . 5 attempts left SU * Open in Reading ViFor net force oh m, = 25m ball F13 m3 mz Since Fiz = 24 0 /N ( we have calculated ) and for ce between m , and mz . Separation b / w both balls a = 69 . 12 G mim 2 x 2 Fiz = (6.67 x10 Nm'Z Q2) 25 m x m ) ( 6 9) 72 = 4 . 63 x 1071 N 9 2 F12 = 4. 63x10-11. X ( 15 kg ) 2 N ( 5:00 m ) 2 12 = 0.417X 10 N (: IN = 10 12 PN ) Fiz = 0. 417 x 10- 12 bN F12 = 4.17 bN Net force oh het 25 m = m, then Thet = Fiz + F, 2 = (4. 17 + 24.0 ) bN Frost = 28.17 bN Andwe b