Question: Based on the above cross-tabulation, the Stata output for the Mantel-Haenszel test is below. cc alcohol smoke, by (marijuana) bd marijuana Odds ratio [95% conf.

 Based on the above cross-tabulation, the Stata output for the Mantel-Haenszeltest is below. cc alcohol smoke, by (marijuana) bd marijuana Odds ratio

[95% conf. interval] M-H weight 1.57037 6727884 3. 706019 5. 075188 (exact)1.838384 6447654 5. 151368 3. 152866 (exact) Crude 1. 846154 . 9833089

Based on the above cross-tabulation, the Stata output for the Mantel-Haenszel test is below. cc alcohol smoke, by (marijuana) bd marijuana Odds ratio [95% conf. interval] M-H weight 1.57037 6727884 3. 706019 5. 075188 (exact) 1.838384 6447654 5. 151368 3. 152866 (exact) Crude 1. 846154 . 9833089 3.471573 (exact) M-H combined 1.673069 9207721 3. 040014 Test of homogeneity (M-H) chi2(1) = 0.07 Pr>chi2 = 0.7987 Test of homogeneity (B-D) chi2(1) = 0.07 Pr>chi2 = 0.7986 Test that combined odds ratio = 1: Mantel-Haenszel chi2(1) = 2. 88 Pr>chi2 = 0. 0898 Based on the above cross-tabulation, the R output for the Mantel-Haenszel test is below. > BreslowDayTest(x) Breslow-Day test on Homogeneity of Odds Ratios data: x X-squared = 0. 065076, df = 1, p-value = 0. 7986 > mantelhaen. test (Q15$alcohol , Q15$smoke , Q15$marijuana, correct=FALSE) Mantel-Haenszel chi-squared test without continuity correction data: Q15$alcohol and Q15$smoke and Q15$marijuana Mantel-Haenszel X-squared = 2.8772, df = 1, p-value = 0.08984 alternative hypothesis: true common odds ratio is not equal to 1 95 percent confidence interval : 0. 9207721 3. 0400141 sample estimates: common odds ratio 1. 673069Question 15 (1 point) ~/ Saved From the above cross-tabulation, we can calculate the odds ratio representing the association between current alcohol use and current cigarette smoking among those who currently use marijuana and those who do not currently use marijuana, respectively. The results of the Breslow-Day test on homogeneity of odds ratios indicate _____ 0 Among those who currently use marijuana, the odds of current alcohol drinking among those who currently smoke cigarettes is 1.84 times the odds of current alcohol drinking among those who do not currently smoke cigarettes. 0 Among those who currently use marijuana, the probability of current alcohol drinking among those who currently smoke cigarettes is 1.84 times the probability of current alcohol drinking among those who do not currently smoke cigarettes. The odds ratios representing the association between current alcohol use and current cigarette smoking among those who currently use marijuana and those who do not currently use marijuana are not statistically different. 0 The odds ratios representing the association between current alcohol use and current cigarette smoking among those who currently use marijuana and those who do not currently use marijuana are both greater than 1

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