Based on the Bear class you were given and the BrownBear class just described, select the correct answers below:

$($a$)$ Select the true statements about the Bear class

If the Bear class implemented the following interface:

public interface Captive

$\{$

void encloseWith$($Bear otherBear$)$;

$\}$

then Bear would have to provide a concrete method with signature encloseWith$($Bear$).$

The equals method in Bear must be overridden in any subclasses to allow instances of subclasses to be passed as arguments.

It is possible to declare a variable of type Bear.

The toString method in Bear could not have called the foodFrequency method in BrownBear even though this uses the method getFoods declared in Bear.

Methods such as setHabitat need to be declared as abstract in order for the Bear class to compile.

As hashCode has not been implemented in Bear, the hashCode method inherited from Object cannot be implemented in any of its subclasses.

The equals method in Bear will consider instances of any subclass equal if they have the same species.

$($b$)$ Select the true statements about the BrownBear class

If the Bear class had included an abstract method:

public void encloseWith$($Bear otherBear$)$;

Then this could have been implemented in BrownBear by a method with the header:

public void encloseWith$($BrownBear otherBear$)$

The foods list in Bear could be sorted in BrownBear using the syntax getFoods$().$sort$()$

It would be possible to clear the list of foods in Bear by means of a method in BrownBear with the code:

public void clearFoods$()$

$\{$

getFoods$()=$ new ArrayList$()$;

$\}$

If the method toString in class BrownBear does not have an @Override annotation then toString from Bear will be executed for objects of class BrownBear.

The class BrownBear must declare a constructor in order to be compiled.

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