Question: Based on this data, 1. What is the standard deviation of the project? (s) 2. What is the projects critical path? 3. What is the

Based on this data,

1. What is the standard deviation of the project? (s)

2. What is the projects critical path?

3. What is the probability of finishing the project in 49 days?

Based on this data, 1. What is the standard

here the predecessor

OS ! Acturity almib Time ESTERILS LE Islack Steele 10.5-ES) A 3.4 6.4.166 4.66) 0 0 4.66 0 0.5 s 3.166 466 48364.66 7826 0 2145 3.833 7-826.11.659 7.89611.657 0.5 124 21166 17:826 9.992 28-325 30.491 20.499 0.5 1232 7-82619-8269-492 1.492 1.666 0.333 F 2.45 3.833-659 15:49211.659 15:42 G 235 3.166.19.826 12.921.492.14.658 1.666. 0.5 H 247.4.166 9.826 13.99/15.65819.824 5.832 0.833 I (3142.833 S 49218-325 15:49218.3.95 O 0.833 (242.166 15.482 07.658 17.658 1.8242.166 0.933 k 3 58 5:166 12.992.18-5844.65819.824.1.666 0.833 L 56106.5 18.325/24.85, 18.325/24.85 O 0.833 M 68.188.333 18:158 26.49119.824 28-157 1.666 1 N 2363.333 24.828.28.192 24.82528.158 0.666 D 152.333 29.158 30.491 28.158 30.491 0.666 P 2373.5 30.491/33.901 30.491 33.991 0 0.833 314614.166 16.491 30-6723.94128.157 -2.5 R 4610 6:333 33.901.90.324 33.911 40324 0 1 S 3 5 125.933 30.45736.49128157.33.99 -2.5 1.5 T 2483 30.65733630-9933.990.333 1 236.3.333 20.65733.9920.657 33.99 46 616-333 33.9940:32. 33.9940.3.04 w 1474 33.99 37.9933.99137.99 0 0.666 1347.833 140.39393,15 4032/43.156 0.5 O 0.5 | 0.666 0.666 Scanned win CamScanner Time=(a+4*m+b)/6z Standard deviation= (b-a)/6 Activity Predecessor A A IOT MO 000 mm www 1 J C G 1 L M N O J, H,K L N DO M P Q R P S Q Q T U Q V TU W VS V X

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