be instantiated with one oie ob element: Object next: Node * Constructs a default node. +getElement0: Object + setElement(Object): void + getNext0: Node setNext(Node): void public Node () ( this (null, nul1) + Constructs a node with an element and link to a null node. * @param element A reference to the element of this node public Node (Object element) ( this (element, null); * Constructs a node with an element and a link to next node. * eparam element A reference to the element of this node public Node (Object element, Node next) this.element-element; this.next next; lowing method can be used to get a reference to the node at position index. * Returns a reference to a specific node at index. *@return The index of a specific node private Node find (int index) ( int position = 0; Node current this.head; while (position index) ( position++; current-current.getNext) return current; 25. Given a multi-node singly lined list, wr position index, the middle of the list. Correct Java syntax is requi ite the code segments in add method that inserts a new node at public void add (int index, object data) .. public void add(int index, object data) throws List IndexoutofBoundsException t 26. Given a multi-node singly linked list( at least five nodes), write the code segments in remove metho that removes the last node from the list.Correct Java syntax is required. (10 points) public void remove (imt-index) (... throws ListindexOutofBounds Exception, public void remove (mt-me ListException(