The balanced equation for the reaction of aluminum metal and chlorine gas is 2Al( s ) +
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Question:
The balanced equation for the reaction of aluminum metal and chlorine gas is
2Al( s ) + 3Cl 2 ( g ) →
2AlCl 3 ( s )
Assume that 0.51 g Al is mixed with 0.29 g Cl 2 .
(a) What is the limiting reactant
(b) What is the maximum amount of AlCl 3 , in grams, that can be produced?
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