Question: Beginning with the strong form for a 1D bar AE du dx = 0 1.01 where E is Modulus of Elasticity (from calibration above),

Beginning with the strong form for a 1D bar AE du dx 

Beginning with the strong form for a 1D bar AE du dx = 0 1.01 where E is Modulus of Elasticity (from calibration above), A is cross-sectional Area, and u is displacement, derive the weak form, assuming linear weight function = N (x)U + N(x)u2, and element length L=1. (Note: Show each step in the derivation fully). The essential and natural boundary conditions are ulx=0 = 0 du dx x= L = S1/E 1.02 1.03 where S1 is the stress at the final increment in the single linear element (reduced integration) simulation in (A). Following the weak form derivation, using the Galerkin Method, determine u for the boundary conditions above. Compare the results of this force driven analysis to the displacement driven analysis in (A).

Step by Step Solution

3.38 Rating (154 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mechanical Engineering Questions!