Below is a partial solution by Laplace transform of an initial value problem (IVP) with a missing part labelled "A". Enter the missing part to complete the correct solution of the IVP. The missing part may be a valueumber/expression. Do not put unnecessary spaces/symbols. IVP : y"- 4y = 0, y(0) = y'(0) = 48 Solution by Laplace transform: STEP REASON L(y" -4y} =L{0} Take the Laplace of both sides. L(y"' )- 41 (y)=0 ($2F(s) - s(A) - (A) ) - 4F(s) =0 Laplace of derivatives. ($2 -4) F (s) = As + A As+ A F (s) = Solve for F(s) . $2-4 What is the missing part "A" in the Laplace transform