Question: Binary mixtures of n - butane and n - hexane produce ideal solutions that obey Raoult's law. A liquid mixture containing 5 0 mol %

Binary mixtures of n-butane and n-hexane produce ideal solutions that obey Raoult's law. A liquid
mixture containing 50mol%n-butane and 50mol%n-hexane at pressure P is heated to a temperature
of 95C, where it exists as a vapour/liquid mixture in equilibrium.
i) If the mole fraction of n-hexane in the liquid phase is 0.75, what is the pressure P(in kPa )?
ii) What molar fraction of the total fluid is vapour? What is the composition of the vapour phase?
iii) If the temperature is maintained at 95C and the pressure increased, at what pressure would all
the vapour condense?
iv) Calculate the condensation (dew) point pressure for the same mixture if maintained at 95C.
v) What is the composition of the liquid at this point?
Antoine equations for vapour pressures ( kPa ) as a function of temperature, T(C) :
n-butane (1):
ln(P1sat)=13.6608-2154.70T+238.789
n-hexane (2 :
ln(P2sat)=13.8193-2696.04T+224.317
Raoult's law:
yiP=xiPisat
 Binary mixtures of n-butane and n-hexane produce ideal solutions that obey

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