binSub.v: A digital circuit that subtracts two $8-$bit $2\text{'}$s complement numbers.

Your task in this assignment part is to create a digital circuit that calculates difference $=$ minuend $-$ subtrahend for three numbers minuend, subtrahend, and difference all encoded as $8-$bit $2\text{'}$s complement numbers.

Input and output format: The interface to the binary subtraction logic is given in binSub.v$.$

Hints: The demonstration code for a $8-$bit negator that finds the negated value of a $8-$bit $2\text{'}$s complement number in the negator$/$ directory should be useful. You may also want to read about half$-$adders and full$-$adders for additional hints for this part. The logic for this part can be co

mpleted in under $150$ lines of code.

Here is given binSub.v:

input $[7$:$0]$ minuend;

input $[7$:$0]$ subtrahend;

output $[7$:$0]$ difference;

wire inv$\_$subtrahend$\_7$;

wire inv$\_$subtrahend$\_6$;

wire inv$\_$subtrahend$\_5$;

wire inv$\_$subtrahend$\_4$;

wire inv$\_$subtrahend$\_3$;

wire inv$\_$subtrahend$\_2$;

wire inv$\_$subtrahend$\_1$;

wire inv$\_$subtrahend$\_0$;

wire negator$\_$carry$\_0$;

wire negator$\_$carry$\_1$;

wire negator$\_$carry$\_2$;

wire negator$\_$carry$\_3$;

wire negator$\_$carry$\_4$;

wire negator$\_$carry$\_5$;

wire negator$\_$carry$\_6$;

wire negator$\_$carry$\_7$;

wire neg$\_$subtrahend$\_7$;

wire neg$\_$subtrahend$\_6$;

wire neg$\_$subtrahend$\_5$;

wire neg$\_$subtrahend$\_4$;

wire neg$\_$subtrahend$\_3$;

wire neg$\_$subtrahend$\_2$;

wire neg$\_$subtrahend$\_1$;

wire neg$\_$subtrahend$\_0$;

assign inv$\_$subtrahend$\_7=$ ~ subtrahend$[7]$;

assign inv$\_$subtrahend$\_6=$ ~ subtrahend$[6]$;

assign inv$\_$subtrahend$\_5=$ ~ subtrahend$[5]$;

assign inv$\_$subtrahend$\_4=$ ~ subtrahend$[4]$;

assign inv$\_$subtrahend$\_3=$ ~ subtrahend$[3]$;

assign inv$\_$subtrahend$\_2=$ ~ subtrahend$[2]$;

assign inv$\_$subtrahend$\_1=$ ~ subtrahend$[1]$;

assign inv$\_$subtrahend$\_0=$ ~ subtrahend$[0]$;

assign negator$\_$carry$\_0=$ inv$\_$subtrahend$\_0$;

assign negator$\_$carry$\_1=$ negator$\_$carry$\_0$ & inv$\_$subtrahend$\_1$;

assign negator$\_$carry$\_2=$ negator$\_$carry$\_1$ & inv$\_$subtrahend$\_2$;

assign negator$\_$carry$\_3=$ negator$\_$carry$\_2$ & inv$\_$subtrahend$\_3$;

assign negator$\_$carry$\_4=$ negator$\_$carry$\_3$ & inv$\_$subtrahend$\_4$;

assign negator$\_$carry$\_5=$ negator$\_$carry$\_4$ & inv$\_$subtrahend$\_5$;

assign negator$\_$carry$\_6=$ negator$\_$carry$\_5$ & inv$\_$subtrahend$\_6$;

assign negator$\_$carry$\_7=$ negator$\_$carry$\_6$ & inv$\_$subtrahend$\_7$;

assign neg$\_$subtrahend$\_0=$ ~ inv$\_$subtrahend$\_0$;

assign neg$\_$subtrahend$\_1=$ negator$\_$carry$\_0^$ inv$\_$subtrahend$\_1$;

assign neg$\_$subtrahend$\_2=$ negator$\_$carry$\_1^$ inv$\_$subtrahend$\_2$;

assign neg$\_$subtrahend$\_3=$ negator$\_$carry$\_2^$ inv$\_$subtrahend$\_3$;

assign neg$\_$subtrahend$\_4=$ negator$\_$carry$\_3^$ inv$\_$subtrahend$\_4$;

assign neg$\_$subtrahend$\_5=$ negator$\_$carry$\_4^$ inv$\_$subtrahend$\_5$;

assign neg$\_$subtrahend$\_6=$ negator$\_$carry$\_5^$ inv$\_$subtrahend$\_6$;

assign neg$\_$subtrahend

$\_7=$ negator$\_$carry$\_6^$ inv$\_$subtrahend$\_7$;

Here is example input and outputs:

TestCase$0$:

$0$

$0$

Answer$0$:

difference $=0$

TestCase$1$:

$1$

$0$

Answer$1$:

difference $=1$

TestCase$2$:

$2$

$1$

Answer$2$:

difference $=1$

TestCase$3$:

$0$

$1$

Answer$3$:

difference $=255$

TestCase$4$:

$1$

$2$

Answer$4$:

difference $=255$

TestCase$5$:

$2$

$2$

Answer$5$:

difference $=0$