Question: Budent Name: Class: Problem 0 6 - 2 0 A Given Data P 0 5 - 2 0 A: Student Name: Class: Problem 0 5

Budent Name:
Class:
Problem 06-20A
Given Data P05-20A: Student Name:
Class:
Problem 05-21A
RANDY'S PARTS CO.
Computations
\begin{tabular}{|c|c|c|c|c|c|c|c|c|}
\hline \multirow[b]{3}{*}{Item} & \multirow[b]{3}{*}{Quantity} & \multirow[b]{3}{*}{Unit Cost} & \multirow[b]{3}{*}{Unit Market} & \multirow[b]{3}{*}{Total Cost} & \multirow[b]{3}{*}{Total Market} & \multicolumn{3}{|c|}{\multirow[b]{2}{*}{Individual Item Lower of Cost or Market}}\\
\hline & & & & & & & & \\
\hline & & & & & & Units & \[
\begin{array}{l}
\text { Cost }\\
\text { per Unit }
\end{array}
\] & Total \\
\hline & & & & & & & & \\
\hline & & & & & & & & \\
\hline & & & & & & & & \\
\hline & & & & & & & & \\
\hline \multicolumn{9}{|l|}{Totals}\\
\hline & & & & & & & & \\
\hline \multicolumn{9}{|l|}{a. Ending inventory using lower-of-cost-or-market rule applied to each individual inventory item:}\\
\hline & & & & & & & & \\
\hline \multicolumn{9}{|l|}{b. Adjustment necessary to write down inventory}\\
\hline & & & & & & & & \\
\hline \multicolumn{9}{|l|}{c. Ending inventory using lower-of-cost-or-market rule applied to total inventory in aggregate:}\\
\hline & & & & & & & & \\
\hline \multicolumn{9}{|l|}{d Adjustment necessary to write down inventory.}\\
\hline
\end{tabular}
c. Ending inventory using lower-of-cost-or-market rule applied to total inventory in aggregate:
d Adjustment necessary to write down inventory.
Given Data P05-21A:
\begin{tabular}{crrrr}
\hline \multicolumn{5}{c}{ RANDY'S PARTS CO.}\\
Item & Quantity & Unit Cost & \multicolumn{2}{c}{\begin{tabular}{c}
Unit \\
Market
\end{tabular}}\\
\hline P1 & 60 & \(\$ \) & 85 & \(\$ \)\\
P2 & 40 & 70 & 90\\
P3 & 80 & 130 & 120\\
P4 & 70 & 125 & 130\\
\hline
\end{tabular}
Budent Name: Class: Problem 0 6 - 2 0 A Given

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